Solve Simultaneous equations: 3x + 4y = 23 & 2x + 3y = 16

We need to cancel one of the variables (the x or y) out. Find the LCM of x or y.e.g. for x --> 6Multiply the WHOLE eqn to get 6x. So multiply the 1st eqn by 2 and the 2nd by 3[1] 6x + 8y = 46[2] 6x + 9y = 48 Then cancel out the x by subtracting one eqn from the other.e.g. [2] - [1] => y = 2Now sub y into one of the eqns that we started with2x + 3(2) = 162x + 6 = 162x = 10x = 5ANSWER: y = 2 & x = 5

EE
Answered by Eric E. Maths tutor

3560 Views

See similar Maths KS3 tutors

Related Maths KS3 answers

All answers ▸

Anton, Barbara and Clive are buying pens from the shop. Anton needs 4, Barbara needs 7, Clive needs 11. Pens only come in packs of 10. How many packs of pens do they need to buy between them?


Expand and simplify (3x + 5)(2x - 4)


Solve for x when x2+16x+28=0


3/8 is equivalent to ?/24. Find the missing number.


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning