What is the total capacitance of a circuit containing a 3microfarad capacitor and a 2microfarad capacitor in series.
For capacitors in series (1/Total capacitance)=(1/capacitance1)+(1/capacitance2).1/C=[(1/(310^-6))+(1/(210^-6))]^-1Total capacitance=1.2*10^-6=1.2microfarad
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