Find Dy/Dx of (x^2+4x)^3

So here we need to use the chain rule in order to differentiate the equation. To start you take the function inside the bracket x²+4x and differentiate it to Du/Dx= 2x + 4 this is known as u. do the you differentiate u³ to Dy/Du= 3u² then multiply Du/Dx by Dy/Du to get Dy/Dx 3u²(2x+4) then substitute u back in to complete the problem 3(x²+4x)(2x+4)