Find Dy/Dx of (x^2+4x)^3
So here we need to use the chain rule in order to differentiate the equation. To start you take the function inside the bracket x2+4x and differentiate it to Du/Dx= 2x + 4 this is known as u. do the you differentiate u3 to Dy/Du= 3u2 then multiply Du/Dx by Dy/Du to get Dy/Dx 3u2(2x+4) then substitute u back in to complete the problem 3(x2+4x)(2x+4)
SO
Related Maths A Level answers
All answers ▸Find where the curve 2x^2 + xy + y^2 = 14 has stationary points
y = 4x^3 - 5/x^2 find dy/dx
Find the tangent to the curve y = x^3 - 2x at the point (2, 4). Give your answer in the form ax + by + c = 0, where a, b and c are integers.
How do you find the gradient of a curve?