If, f(x) = 8x^3 + 1 / x^3 . Find f''(x).
f(x) = 8x3 + 1 / x3 >>> f(x) = 8x3 + x-3
f'(x) = 3(8x2 ) + -3(x-4) >>> f'(x) = 24x2 - 3x-4
f''(x) = 2(24x1) - 4(-3x-5)
Final Answer, f''(x) = 48x + 12x-5
SS
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