If, f(x) = 8x^3 + 1 / x^3 . Find f''(x).

f(x) = 8x³ + 1 / x³ >>> f(x) = 8x³ + x^-3
f'(x) = 3(8x² ) + -3(x^-4) >>> f'(x) = 24x² - 3x^-4
f''(x) = 2(24x¹) - 4(-3x^-5)
Final Answer, f''(x) = 48x + 12x^-5