Find dy/dx when y=2x^(4)+3x^(-1)

To differentiate this equation we use the power rule. This means that we times the power by the coefficient, this now becomes our new coefficient. Then you subtract 1 from the old power and this becomes your new power. So dy/dx=8x^(3)-3x^(-2).

RC
Answered by Rio C. Further Mathematics tutor

3118 Views

See similar Further Mathematics GCSE tutors

Related Further Mathematics GCSE answers

All answers ▸

Point A lies on the curve: y=x^2+5*x+8. The x-coordinate of A is -4. What is the equation of the normal to the curve at A?


Express (7+ √5)/(3+√5) in the form a + b √5, where a and b are integers.


The coefficient of the x^3 term in the expansion of (3x + a)^4 is 216. Find the value of a.


How do you use derivatives to categorise stationary points?


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning