how find dy/dx of parametric equations.

We start with parametric equations of x=2t+3 and y=3t^2+3t+2.
To find dy/dx, we need to work out either (dy/dt)/(dx/dt) or (dy/dt)*(dt/dx). This makes the dt's cancel each other out, allowing us to find dy/dx. First, we will differentiate our y=3t^2+3t+2. This gives us dy/dt=6t+3. To find dx/dt, differentiate x=2t+3 to give dx/dt=2.We can then do (dy/dt)/(dx/dt) to give (6t+3)/2=3t+1.5

SW
Answered by Samuel W. Maths tutor

2849 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

Why is 2 + 2 not equal to 12?


integrate cos(2x) + sin(3x)


Solve the inequality x < 4 - |2x + 1|.


differentiate y=e^2x


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences