how find dy/dx of parametric equations.

We start with parametric equations of x=2t+3 and y=3t^2+3t+2.
To find dy/dx, we need to work out either (dy/dt)/(dx/dt) or (dy/dt)*(dt/dx). This makes the dt's cancel each other out, allowing us to find dy/dx. First, we will differentiate our y=3t^2+3t+2. This gives us dy/dt=6t+3. To find dx/dt, differentiate x=2t+3 to give dx/dt=2.We can then do (dy/dt)/(dx/dt) to give (6t+3)/2=3t+1.5

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Answered by Samuel W. Maths tutor

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