Let R denote the region bounded by the curve y=x^3 and the lines x=0 and x=4. Find the volume generated when R is rotated 360 degrees about the x axis.

The area of a circle is given by (pi)r2 and the area generated by R can be considered as an infinite number of circular areas.

Thus, we can write the area generated by R as the integral of (pi)(x3)2 between x=0 and x=4.

The (indefinate) integral is: (pi)6x5

so the area is: (pi)6(45-05)=(pi)6(1024-0)

                                      =6144(pi)

SB

Related Maths A Level answers

All answers ▸

Find the area enclosed between the curves y = f(x) and y = g(x)


Integrate 4x^3 - 3x + 6


Integrate 5sinxcosx + 5cosx


By consdering partial fractions find the integral of (1-x)/(5x-6-x^2) between x = 1 and x = 0, give your answer in an exact form.