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differentiate y = 4x^3(12e^-4x) with respect to x

y = 4x3e-4x   u = 4x3  v = e-4x du/dx = 12x2 dv/dx = -4e-4x using the product rule; vdu +udv  vdu + udv = 12x2e-4x - 16x3e-4x

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Answered by Lewis M. • Maths tutor

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