differentiate y = 4x^3(12e^-4x) with respect to x

y = 4x3e-4x   u = 4x3  v = e-4x du/dx = 12x2 dv/dx = -4e-4x using the product rule; vdu +udv  vdu + udv = 12x2e-4x - 16x3e-4x

LM
Answered by Lewis M. Maths tutor

3848 Views

See similar Maths A Level tutors

Related Maths A Level answers

All answers ▸

How do I differentiate y=(4+9x)^5 with respect to x?


How/when should I use the product rule for differentiation?


The straight line with equation y = 3x – 7 does not cross or touch the curve with equation y = 2px^2 – 6px + 4p, where p is a constant. Show that 4p^2 – 20p + 9 < 0.


y =(4x)/(x^2+5) (a) Find dy/dx, writing your answer as a single fraction in its simplest form. (b) Hence find the set of values of x for which dy/dx<0


We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2026 by IXL Learning