Find the equation of the tangent to the curve y=x^2+5x+2 at the point where x=5

Step 1: Differentiate the equation of the curve (this gives a function for the gradient of the curve at a specific point)Step 2: Substitute x value into the differential of the curve to obtain gradient (m)Step 3: Obtain y co-ordinate by substituting x into equation of the curveStep 4: Substitute y, x and gradient (m) values into general equation of a line (y=mx+c)Step 5: Work out the value of the y intercept (c)Step 6: Substitute values of gradient (m) and y intercept (c) into general equation of a line (y=mx+c) for the final answer

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Answered by Muhammed R. Maths tutor

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A curve has equation y = 7 - 2x^5. a) Find dy/dx. b) Find an equation for the tangent to the curve at the point where x=1.


differentiate with respect to x : y = x^2 -5x


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