The point P has coordinates (3, 4) The point Q has coordinates (a, b) A line perpendicular to PQ is given by the equation 3x + 2y = 7 Find an expression for b in terms of a

y = -3/2x + 7/2gradient = -3/2
gradient of perpendicular = 2/3
y = 2/3x + c
sub in given values of x and y to find c
y = 2/3x + 2
sub in a and b, so:
b = 2/3a + 2

UA
Answered by Usamah A. Maths tutor

5432 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Expand (2x+3)(x-2)


Simplify (2sin45 - tan45) / 4tan60


Simplify (m-7)(m+3)/6(m+3)


How do I rearrange this equation for x? y=(x+2)/(3x-1) +2


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences