Solve the following simultaneous equation: 3x+2y=20 and x+4y=20

In this example, we want to find values for both x and y which are our unknowns. 

So we start by rearranging x to be on its own but still in terms of y. We then can plot it into the next equation. 

Hence we get the following equations:

.  x=20-4y (See, 4y has been taken over to the other side and hence the sign changes)

.  3x+2y=20

Then we substitute this new value of x in the other equation:

3(20-4y)+2y=20

60-12y+2y=20 (we have multiplied out the 3 and its bracket to simplify)

-10y=20-60 (make sure you change the sign when taking the 60 across!)

-10y=-40

-y=-4 (here we divided 40 by 10)

y=4 (the minus signs cancel each other out)

Now that you've found y we must plot it back into the original equation to find x:

x+4y=20

x+4(4)=20

x+16=20

x=20-16

x=4

Therefore, x=4 and y=4.

Answered by Phillipa S. Maths tutor

7337 Views

See similar Maths 13 Plus tutors

Related Maths 13 Plus answers

All answers ▸

How do I know which calculation to do first in questions with multiple operations (e.g. 2 x 3 - 2 x 5)?


x^2-5x-50=0. Solve for the positive value of x


Write 0.185 as a percentage


Simplify the following expression fully: 4x + 5y + 6x - 7y


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2024

Terms & Conditions|Privacy Policy