Can you solve the following 2 simultaneous equations; y=6x-2 and x^2-4x+19=y?

y=6x-2

x2-4x+19

Both equations are equal to Y, hence can be substituted into each other;

6x-2= x^2-4x+19

Now we only have X terms in our equations

Bring all the like X terms together, and make equation equal to 0

  1. 6x-2= x^2-4x+19
  2. 6x= x^2-4x+19+2
  3. 6x= x^2-4x+21
  4. 0= x^2-4x+21-6x
  5. 0= x^2-10x+21

Now we have a simultaneous equations which we can factorise

0=(x-7)(x-3)

We can now solve this as either x-7 must equal 0 or x-3 must equal 0

0=x-7………………………………x=7

Or

0=x-3………………………………x=3

Hence answer is x=7 or 3

MC
Answered by Mohammed C. Maths tutor

6440 Views

See similar Maths GCSE tutors

Related Maths GCSE answers

All answers ▸

Show that (x+1)(x+2)(x+3) can be written as ax^3+bx^2+cx+d


1i) solve x^2-4x-21=0


How can you differentiate when to use SohCahToa and when to use the sine/cosine rules?


Solve the simultaneous equation: x+2y=8 and 2x+y=10 - using a calculator


We're here to help

contact us iconContact usWhatsapp logoMessage us on Whatsapptelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

© MyTutorWeb Ltd 2013–2025

Terms & Conditions|Privacy Policy
Cookie Preferences