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Using the substitution u = sec(z)=> du = sec(z)tan(z) dz.So, the integral ∫ y dz = ∫ sec(z)tan(z)/sqrt(sec(z)) dz=> ∫ y dz = ∫ 1/sqrt(u) du = 2sqrt(u) + C = 2sqrt(sec(z)) + C.

First, you will need to differentiate the function with respect to x. Finding dy/dx.For polynomials, this is done by taking one away from the old power and multiplying the coefficient by the old power and...

quadratic equation where the coefficients of the quadratic equation: ax^2 + bx + c are substituted into the formula: [-b +- (b^2 - 4ac)^0.5] / 2a. The roots are what x equalscompleting the square where th...

To factorise an equation like this we must first make the equation equal to 0 therefore it becomes: x^2+10x+21.Now we have the equation in a way that we can work with it we can factorise.To do this we nee...

Firstly we need to identify what is the underlying principle of this question and what are the assumptions we have to make. We are given some information about the cleaning process in a hotel. The variabl...