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x = ln (sec (2y))

The chain rule states that d/dy f (g (y)) = f'(g(y)). g'(y)

Here g(y) = sec(2y) so g'(y) = 2.sec(2y).tan(2y)

And f(y) = ln (y) so f'(y) = 1 / y

Thus dx/dy = (...

0001 1111 AND 1010 1010 = 0000 1010

0001 1111 OR 1010 1010 = 1011 1111

0001 1111 XOR 1010 1010 = 1011 0101

print("Enter two numbers. I will tell the highest of the two.") num1 = input("Number 1: ") num2 = input("Number 2: ") if (num1 == num 2) print ("They are the same"....

x² - 8x + 5 = 0 => (x² - 8x + 16) - 11 = 0 =>(x - 4)² = 11 =>x - 4 = +- sqrt(11) =>x = 4 +- sqrt(11)

Vaya, vayas, vaya, vayamos, vayáis, vayan