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how am I meant to solve sq.root(6^2+8^2) = cube.root(125a^3) when one side is squared and the other is cubed?

first of all, have a look at each side separately to see you you can cancel anything down.e.g. the square and square root can cancel out. => sq.root(62+82) = 6+8on the otherside, ...

RS
Answered by Rosalind S. Maths tutor
7313 Views

what is the value of 27 to the power of -2/3

27-2/31/(272/3)1/(271/3)21/32= 1/9

LR
Answered by Lakshmi R. Maths tutor
5505 Views

Given a curve with parametric equations, x=acos^3(t) and y=asin^3(t), find the length of the curve between points A and B, where t=0 and t=2pi respectively.

The length of an arc between two points on a curve can be calculated in two ways; as the integral of ((dy/dx)^2 + 1)^1/2 between the values of the points, or as the integral of ((dy/dt)^2+(dx/dt)^2)^1/2 b...

JW
5226 Views

solve 125^(1/3)*2^(-3)

To find 1251/3 we have to solve x3 = 125 => This gives x=5 Then we have 2-3 is equal to 1/(23) => This is equal to 1/8So to answer the question we have 5*...

RR
Answered by Robbie R. Maths tutor
4245 Views

solve x^3+2x^2+x=0

factorise x3+2x2+x=0 => x(x2+2x+1)=0 => x(x+1)(x+1)=0 => x(x+1)2=0 => This leads to x=0 and (x+1)2=0 so x=0 and x+1=0 => Giving us the...

RR
Answered by Robbie R. Maths tutor
5786 Views

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