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Under a perfectly competitive market, there are a large number of buyers and sellers, where each of them are price-takers. If we imagine a supply and demand diagram, the S=D at equilbrium. If firms are in...

First lets times both sides by (6x -1) y(6x - 1) = 4(2 + x) now lets expand the brackets 6xy - y = 8 + 4x now lets move all the ones with x as a factor onto one side of the equation and the rest on the ot...

Solution: 

We can first write down the formula for the area of a circle which is pi*(radius)^2.

The radius of the circle is half the diameter, so radius= 1/2(8)=4cm.

Therefore the are...

|Z| = sqrt(1/2^2 + (sqrt(3)/2)^2) = 1 arg(Z) = arctan((sqrt(3)/2)/(1/2)) = pi/3 Z = cos(pi/3) + jsin(pi/3) Z = e^j(pi/3) Apologies for the use of sqrt(), I have no way yet of using the symbol on my laptop...

First we must differentiate the equation with respect to x. To differentiate you must multiply the coefficient (number in front) by the power of x, then subtract 1 from the power. So here we find dy/dx = ...