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A curve is defined for x>0 as y = 9 - 6x^2 - 12x^4 . a) Find dy/dx. b) Hence find the coordinates of any stationary points on the curve and classify them.

a) y = 9 -6x^2 - 12x^4 

dy/dx = -12x - 48x^3 

b) At stationary points dy/dx = 0. 

-12x - 48x^3 = 0 

48x^3 + 12x = 0 

4x^3 + x = 0

x (4x^2 + 1) = 0 

Either ...

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Answered by Olivia W. • Maths tutor
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