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A curve is defined by the parametric equations; x=(t-1)^3, y=3t-8/(t^2), t~=0. Find dy/dx in terms of t.

dy/dx=(dy/dt)*(dt/dx); dy/dt=3+16t-3; dx/dt=3(t-1)2; dt/dx=1/3(t-1)2; dy/dx=(3+16t-3)/3(t-1)2

NC
Answered by Nadia C. Maths tutor
3874 Views

Solve the following equation: x^(3) - 6x^(2) + 11x - 6 = 0

x3 - 6x2 + 11x - 6 = 0
Let (x-a)(x-b)(x-c) = x3 - 6x2 + 11x - 6=> abc = -6 and a + b + c = -6 From abc=-6, find the possibilities of their values: (1,2,...

EH
Answered by Ellie-May H. Maths tutor
7517 Views

What is EMF? How do we test for it?

Electromotive Force (EMF) is the measure of how much energy a source like a battery gives to the charges in a circuit. As with most things, this energy source is not 100% efficient, and has an associated ...

KM
Answered by Kieran M. Physics tutor
4498 Views

What is a dative covalent bond?

A dative covalent bond, or coordinate bond, is a bond where there is 1 pair of shared electrons between two atoms. The difference relative to a covalent bond is that in a dative covalent bond these electr...

AN
Answered by Angela N. Chemistry tutor
6876 Views

How would I differentiate y = 3xy + 2x^2 + x^2y^2 ?

Since this problem contains both xs and ys on the right hand side, we need to use implicit differentiation. This is where we use the chain rule to differentiate with regards to x the terms which contain y...

EO
Answered by Emelia O. Maths tutor
16766 Views

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