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(i) Prove sin(θ)/cos(θ) + cos(θ)/sin(θ) = 2cosec(2θ) , (ii) draw draph of y = 2cosec(2θ) for 0<θ< 360°, (iii) solve to 1 d.p. : sin(θ)/cos(θ) + cos(θ)/sin(θ) = 3.

For (i) Start by looking at left hand side of the equation. It is usually much easier to reduce large expression into smaller ones. So, LHS = sin2(θ) +cos2(θ)/ sin(θ)cos(θ). Since, s...

RK
Answered by Rabin K. Maths tutor
11909 Views

What is Strict Liability?

Crimes which are strict liability require no proof of mens rea in relation to one or more aspects of the actus reus. It could also be considered actionable per se as the crime speaks for itself. Strict li...

HM
Answered by Harriet M. Law tutor
4493 Views

How do I answer a word choice question in close reading or comprehension?

When answering close reading questions about word choice one of the easiest ways to think about it is what are the CONNOTATIONS of a word - a fancy way of saying what do the words the author has chosen ma...

MC
Answered by Megan C. English tutor
3721 Views

Of the following 4 equations, 3 of them represent parallel lines. Which is the odd one out?

  1. 2y - 3x = 4 2) -12x = 4(1 - 2y) 3) y - 5 = 3(x - 1)/2 4) 3(y - x) = 4 - y This question relies on the student's understanding of parallel lines as well as their ability to rearrange equations. The k...
WS
Answered by Wayne S. Maths tutor
3388 Views

A particle is undergoing circular motion in a horizontal circle, that lies within the smooth surface of a hemispherical bowl of radius 4r. Find the distance OC (explained in diagram) if the angular acceleration of the particle is equal to root (3g/8r).

Resolve the reaction force caused by the weight, mg, of the particle horizontally and vertically. Rsin(theta) = mg Rcos(theta)=m(CP)w^2 where w = root (3g/8r).thus tan(theta) = 8r/3CPconsider the right an...

EB
2598 Views

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