Search over 10,000 free study notes

First it is important to identify that this is an integration by parts question as it can't be solved by substitution.
Let I = integral for ease of notation.Write out integration by parts formula I(...

To integrate you add one to the power and divide by the new power, so this becomes:3t³/3 + 7t²/2 simplifying to t³ + 7/2 t²If we were just performing indefinite...

Let I = integral[(lnx)/x^2 dx] for simplicity.Firstly, we realise we must use integration by parts. This is:Integral [u(x)v'(x) dx] = u(x)v(x) - Integral[u'(x)v(x) dx]So we can see that, by letting u(x)=l...

Differentiate y with respect to x using quotient rule:y'=[(1/x)(5x^2)-(10x)(lnx)]/(lnx)^2 =[5x-10xlnx]/(lnx)^2Stationary points occur when y'=0, so when y'=0 we have:5x-10xlnx = 0x(5-10lnx)=0So x=0 or 5...

The turning point of a curve is the point at which the gradient is 0 as from there it stops rising and starts falling or vice versa. To find this we differentiate y with respect to x (dy/dx) to find the g...