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Integrate ln(x) by parts with u=ln(x) and dv/dx=1 Gives x+xln(x)-x+c Therefore xln(x)+c
integral of 4x3 with respect to x =x4+C
3x2 6x
Note that you can not take a positive base log of a negative number. log5(x2-5) - log5(x) = 2log5(2) => log5((x2-5)/x) = log5MLAnswered by Milan L. • Maths tutor3425 Views
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