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Integrate, y= 3x² -1/x

 1{³ 3x² - 1/x dx = [x-lnx]³₁= (3-ln3)-(1-ln1) = 3-ln3-1+0= 2-ln3

f(1)=0

f(x)=(x-1)(x+4)(x-2)

We are given: y = 4x^3  – 5/(x^2) To find the dy/dx we are going to use the power rule, from the power rule differentiating x^n gives n*x^n-1, so from our equation differetiating x^3 will give 3x^2, but w...

First you want to draw the complez number on to an argand diagram, using which you will find the modulus and argument. This is how to do so: The modulus is to be obtained using pythagoras (which will be e...

General form of a Geometric series: a + ar + ar^2 + ar^3 + ar^4 + … First three terms: 10 + 100.2 + 100.2^2 = 10 + 0.2 + 0.04Nth Term of a Geometric Series: ar^n-1 where there are n terms Proof o...