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Solve via Integration by parts:

let u=2x and dv/dx=e^x

the function that is u and the one that is dv/dx is given by LATHE (easier to explain on whiteboard)

make the table: u...

Using the intergarting rules, you would add a power then divide that new number to the coefficent so you would get 5x^3 and just add one x to the 7 and dont forget the c. So the end answer would be 5x^3 +...

log_{x} (7y+1) - log{x} (2y) =1 --> log_{x} [(7y+1)/2y]=1 (y =/= 0, Rules of logarithms i.e. difference of logarithms) --> x = [(7y+1)/2y] (x>0, Rules of logarithms i.e. log_{x} x = 1) --> 2yx...

A/(x-2) + B/(x+1) + C/(x+1)^2

if y=3x^2 + x -4 

then 

dy/dx = 6x + 1

setting this equal to zero gives

6x + 1 = 0

so then

x = -1/6

putting this x value back into the original equation gi...