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y = 4x^3-5x^-2 dy/dx = 12x^2+10x^-3
3tan(k)-1=sec^2(k) () We want to get this in the form of a quadratic equation in a single variable, and in this case the easiest variable is tan(k). To do this we use the trigonometric identity sec^2(...
Use the identity cos^2(x)+sin^2(x)=1, to change the 5sin^(x) into 5-5cos^2(x) and rearrange. Let y=sin(x) and solve the rearranged quadratic (6y^2-3y-3) for y and find the value of x for each solution. y=...
If I were to get the job, I would get a writing board to help explain this. But to approach this question, it's a good idea to draw the graph. You know that the tangent line is a straight line and as the ...
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