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This kind of question demonstrates the fact that certain problems can be expressed in much simpler ways so they be easily solved.  In this particular example the question can be simplified to "int...

This example provides us with a better understanding of how "Integration by parts" works. Building an extensive knowledge of Integral calculus requires a lot of work, but once the basics are ...

We can express the equation of any circle in the form (x - a)^2 + (y- b)^2 = r^2. The centre of the circle is then the point (a, b) and its radius is ...

The gradient of a line in the form y = ax + b, where a and b are some numbers, is the number a.

So we need to get the equation 3x + 5y = 7 into the above...

First we want to calculate the derivative of y. To do this we use the product rule:If we rewrite y as y = uv, then dy/dx = vdu/dx + udv/dx.Here, we have u = x and v = cos(x).That means du/dx = 1 ...