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Firstly, we need to look at completing the square. This is done by looking at the x^2-8x section of the equation. We need to find a way of converting it to the format of (x-a)^2. If you remember, when ...

Firstly, we must recognise that the equation contains two different trigonometric functions (sec() and tan()) and therefore we must rewrite one of these functions in terms of the other. Therefore we will ...

Rearrange the equation to give sin3θ=(sqrt3)cos3θ, then divide through by cos3θ to give sin3θ/cos3θ=sqrt3. We know from our trig identities that sinx/cosx=tanx, so our equation now becomes tan3θ=sqrt3. Us...

To start off with let 2/P(P-2)=A/P + B/(P-2) making the RHS of the equation one fraction gives : (A(P-2)+B(P))/P(P-2). So now we can compare the numerators (as the denominators are the same): A(P-2)+B(P)=...

If line L is parallel to line A it will have the same gradient; in this case, the letter a in the equation y=ax+b represents the gradient. Therefore line L will be of the form y=4x+b. To find the value of...