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When integrating a long chain of functions, we can integrate each term seperately and combine them. Let us now integrate:∫21x⁶dx = 21∫x⁶dx. Using the Power Rule [∫x^adx = (...

Write as y=uv u=x v=e^x

du/dx=1 dv/dx=e^x 

Using the product rule, dy/dx=vdu/dx + udv/dx

So dy/dx=e^x(1)+x(e^x...

So we have the equation initially in the form 3^(5x-2)=4^(6-x), and as the solution involves log10, then  a sensible first move would be to take log10 of both sides, giving log10(3^(5x-2)) = log10(4^(6...

Starting on the left hand side we can expand out the brackets to get:
(sinx + cosx)(sinx + cosx)
sin²x+sinxcosx+sinxcosx+cos²x
Grouping together the like terms we can ...