Top answers

Physics
A Level

In a particle accelerator, you accelerate an electron. Afterwards, you measure it's energy to be 350 keV. Tell my why you can't find the speed from this energy using your knowledge of classical mechanics.

In order to see what the problem is, I will attempt to find this speed. 350keV=5.6110-14 J Ek=1/2 * mv2 =>  v=sqrt(2Ek/m) By plugging in numbers, we...

CP
Answered by Cezar P. Physics tutor
2190 Views

What is the mathematical relationship between the frequencies of musical notes that we perceive identical, but at different octaves?

Humans have a logarithmic perception of the majority of uncountable and some countable things. A0, which is percieved as the basic note, has a frequency of 27.50 Hz. A1=55 Hz, and A<...

CP
Answered by Cezar P. Physics tutor
3068 Views

A basketball player throws his ball vertically upwards with an initial speed of v=40 m/s. Ignore air resistance. What is the speed of the ball at half of the maximum height?

Since we are neglecting air resistance the energy of the ball is conserved. We set the gravitational potential energy to be U=0 at h=0. Applying conservation of energy at h=0 and h=hmax , we ge...

AM
5462 Views

You are asked to find the Young modulus for a metal using a sample of wire. *(a) Describe the apparatus you would use, the measurements you would take and explain how you would use them to determine the Young modulus for the metal.

Apparatus: The wire is secured by a clamp and clamp stand A hanging mass is attached to the end of it, where the mass hung can...

RH
Answered by Robert H. Physics tutor
7834 Views

A cable with a diameter of 6mm is used to lift crate. Calculate the mass of the crate required to create a stress of 350 MPa.

Let's begin with the definition of stress:

Stress = F/A

First, we need to recall that the force the weight of the crate will exert on the cable will be equal to:

F= m*g

We know...

AD
Answered by Abdel D. Physics tutor
2319 Views

We're here to help

contact us iconContact ustelephone icon+44 (0) 203 773 6020
Facebook logoInstagram logoLinkedIn logo

MyTutor is part of the IXL family of brands:

© 2025 by IXL Learning