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Maths
GCSE

Draw a graph of x = (y+4)/4.

Note: There are multiple ways to do this, so find a way that works for you!Step 1: Get rid of the fraction.Step 2: Rearrange the new formula into y = mx + c.Step 3: Find the y-intercept and the x-intercep...

TN
Answered by Tarin N. Maths tutor
2742 Views

How do you solve simultaneous equation where one of them involves powers?

Example: y - 3x = 2 , x2 + y2 = 4 y= 3x + 2 x2 + (3x+2)2 = 4 10x2+ 12x + 4 = 4 10x2+12x=0 x(10x+12)=0 x=0 or x=-1.2 y=30 + 2 = 2 (0,2)...

LF
Answered by Luke F. Maths tutor
2645 Views

Solve the Simultaneous equations x^2 + y^2 =29, y-x=3.

y=x+3, Substitute into equation 1 : (x^2) + (x+3)^2 = 29Expand the Brackets : (x^2) + (x^2 + 6x + 9) = 29Collect like terms : 2x^2 + 6x - 20 = 0Take out a factor of two : x^2 +3x -10 = 0Factorise : (x-2)(...

TM
Answered by Theo M. Maths tutor
3231 Views

Simplify the following expression: ( (x^5) / (x^2) ) ^ 4

For this question it is key to remember the indices laws. The ones you need to recall for this question are: xa / xb = xa - b, and (xa)b = xa * ...

SJ
Answered by Shafaan J. Maths tutor
2897 Views

Express x^2 + 10x – 3 in the form (x + p)^2 + q

= We start by halfing the 10 and putting x + 5 in a bracket = (x + 5)^2 = Opening these brackets give us x^2 + 10x + 25 = To make the 25 the same as - 3 we have to minus 28 = Therefore the answer is = (x ...

HP
Answered by Haasan P. Maths tutor
6648 Views

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