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Maths
GCSE

Solve 7(x+2)=5x+21

The first thing we must realise is that there are brackets in this equation and thus this has to be dealt with. We expand out the brackets on the left side by multiplying 7 by x and 2 to obtain '7x+14'. W...

Answered by Maths tutor
3123 Views

Draw a graph of x = (y+4)/4.

Note: There are multiple ways to do this, so find a way that works for you!Step 1: Get rid of the fraction.Step 2: Rearrange the new formula into y = mx + c.Step 3: Find the y-intercept and the x-intercep...

TN
Answered by Tarin N. Maths tutor
2622 Views

How do you solve simultaneous equation where one of them involves powers?

Example: y - 3x = 2 , x2 + y2 = 4 y= 3x + 2 x2 + (3x+2)2 = 4 10x2+ 12x + 4 = 4 10x2+12x=0 x(10x+12)=0 x=0 or x=-1.2 y=30 + 2 = 2 (0,2)...

LF
Answered by Luke F. Maths tutor
2532 Views

Solve the Simultaneous equations x^2 + y^2 =29, y-x=3.

y=x+3, Substitute into equation 1 : (x^2) + (x+3)^2 = 29Expand the Brackets : (x^2) + (x^2 + 6x + 9) = 29Collect like terms : 2x^2 + 6x - 20 = 0Take out a factor of two : x^2 +3x -10 = 0Factorise : (x-2)(...

TM
Answered by Theo M. Maths tutor
3123 Views

Simplify the following expression: ( (x^5) / (x^2) ) ^ 4

For this question it is key to remember the indices laws. The ones you need to recall for this question are: xa / xb = xa - b, and (xa)b = xa * ...

SJ
Answered by Shafaan J. Maths tutor
2798 Views

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