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Maths
GCSE

Prove that the product of 3 consecutive integers is divisible by 6

If you set the three consecutive integers to be n, n+1 and n+2, we know that one of the numbers must be divisible by 2 and one must be divisible by 3. For example if you had your three numbers as: 5, 6, 7...

SK
Answered by Shreeya K. Maths tutor
14621 Views

Expand and simplify: 5(x +y) + 3(4x-2y)

I'd first explain how expansion works, and that the first step is to expand the first bracket as shown below:The first bracket expands to: 5x + 5y which equals 5x + 5yThe next step I'd show would...

HJ
Answered by Harvey J. Maths tutor
3984 Views

Simplify fully (x^2 + 3x)/(4x + 12)

You should begin by factorising the numerator and denominator, in order to determine what would go into both parts of the fraction.As you can see, x2 and 4x have 'x' in common, and 3x and 12 ha...

MJ
Answered by Matthew J. Maths tutor
3701 Views

Simplify completely: 3x^2 - 14x +5 /2x^2 -10x

Ideally you're aiming to find common factors on both sides of the fraction that cancel out. Firstly we can break this question down into two bits. First bit is factorising 3x^2 -14x+5. Factorizing this wo...

DB
Answered by Diya B. Maths tutor
2743 Views

Write x^2 + 6x - 10 in the form ((x+a)^2)+b?

To find the value of a divide the coeffecient of x. Here this would be 6/2 which = 3. If we were to expand (x + 3)^2 + b this would give us:x^2 + 3x +3x + 3^2 +b which simplifies to x^2 + 6x + 3^2 + b. If...

GG
Answered by Gunalini G. Maths tutor
13523 Views

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