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Start by selecting a variable to eliminate from the equations. --> Select x in this case.Take the second equation and multiply by 2. --> 2x + 6y = 38Subtract the first equation from this answer. --&...
First, we notice how there is only an 'x2' term and a number in this expression. Also notice that the number, 9, is a square number. Whenever you have an expression that looks like 'x2RAAnswered by Rebecca A. • Maths tutor26124 Views
Initially we have two unknown variables, so we want to eliminate one of the variables (x) to solve for the other (y). The LCM of 6 and 4 is 12, so multiply each equation such that the coefficient of x is ...
7x = 4yx=4y/7If we insert this into our other equation.4y/7 + y = 8811y/7 =88y = 56As we knowx =4y/7X= 4*56/7 = 32Then we can work out the answer X - Y = 32 - 56 = -24
This question is slightly trickier than normal simultaneous equations, because we have values to the power of 2. What we can do is make either y or x the subject of the 2nd equation (y-x = 3). For this ex...
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