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Maths
GCSE

Solve the Simultaneous equation: 6x+3y=13, 14x-9y=9?

First we need to eliminate one of the Variables, to have an equation dependant on one variable. The coefficient for y in equation two is a third of the coefficient of the y in the second equation. Therefo...

MM
Answered by Matthew M. Maths tutor
2969 Views

How to find the longest side of a right-angled triangle if we are given the two other sides?

We can find the longest side of a right angled triangle (also called the hypotenuse) by using Pythagoras' Theorem and considering the lengths of the two other sides given to us. Pythagoras' Theorem is wri...

DC
Answered by Denzel C. Maths tutor
17912 Views

make x the subject of 5(x-3) = y(4-3x)

step 1 ; expand the brackets5x - 15 = 4y - 3xystep 2 ; group together x values on one side5x + 3xy = 4y + 15step 3 ; single out xx (5+3y) = 4y +15step 4 ; make x the subjectx = (4y + 15) / (5+3y)

SA
Answered by Sofia A. Maths tutor
4727 Views

Write down the length of side "a"

Using Pythagoras' theorem: a2 = b2 + c2You can use the length of the other two sides to calculate a.

RK
Answered by Rhys K. Maths tutor
2784 Views

Solve these simultaneous equations 2y+x=8, 1+y=2x.

When solving simultaneous equations the first step is to take one of the equations and rearrange it to make one of the terms the subject. In this case lets take the equation 1+y=2x. Take the 1 over to the...

LK
Answered by Lewis K. Maths tutor
3515 Views

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