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15a2+ab-6b2 =(?a+?b)(?a-?b) Factors of 15= 3 and 5 Factors of 6= 2 and 3 If we try (3a+2b)(5a-3b) that gives us 15a2+10ab-9ab-6b2 = 15a2+ab-6b2 therefore the answer is (3a+2b)(5a-3b)
5(x+4)-3(2+3x)
Expand first bracket
5x+20-3(2+3x)
Expand second bracket
5x+20-6-9x
simplify
14-4x
This involves the product rule for counting. Step 1: Identify the possible numbers for the first digit 5, 6, 7, 8 or 9 (5 in total) Step 2: Identify the possible numbers for the second digit 2, 3, 5 or 7 ...
15a2+ab-6b2
=(?a+?b)(?a-?b)
factors of 15= 3 and 5
factors of 6= 2 and 3
if we try (3a+2b)(5a-3b) that gives us 15a2+10ab-9ab-6b2 ABAnswered by Aayushi B. • Maths tutor2766 Views
Let h be the height of the table. Let the edges of the fridge be A touching the ceiling, B touching the table and C touching the floor. Let D be the point on the ceiling vertically above B and E be the po...
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