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A stationary point is a point where dy/dx = 0.First we need to find dy/dx. This is done by differentiating y term by term to get dy/dx = 3x^2 - 6x - 9.Setting this equal to zero, we need to solve 3x^2 - 6...
rearrange by taking away 2 and adding 1
x2 + 14x + 22 = 4x -21) First you should arrange the equation into the format ax2 + bc + c = 0. This gives x2 + 10x + 24 =02) Factorise into (x+n)(x+m) = 0. To work...
Typically consists of a rundown of all 6 function transformations in a way which is interactive with the student.
Start to solve by substitution: eqn 1 x^2 + y^2 = 25eqn 2 y - 3x = 13 => y = 3x + 13Substitute eqn 2 into 1: x^2 + (3x +13)^2 = 25expand and simplify the equation ...5x^2 + 39x + 72 = 0RRAnswered by Rosita R. • Maths tutor2744 Views
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