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When multiplied together the gradients of perpendicular lines should give the answer - 1So: x₁x₂ = -1x₁ = 2 x₂ = -1/2It crosses through the point (1,2)y = ax+ b...

We know the values for the 2nd and 5th terms and already have the 2nd term as an equation but not the 5th. Therefore, we need to start by working out what exactly the 5th term is in terms of a and b. From...

To solve a quadratic equation of the form Ax² + Bx + C = 0, where, in this example, A=1, B=7 and C=6, we need to factorise the left-hand side of the equation. To do this we first need to write ...

-4<x<2Work out using whiteboard

The easiest way to solve these equations is by substitution. Rearrange the 6y=-x+64 equation into the form of x=64-6y. Replace x in the other equation with x=64-6y to produce y+5(64-6y)=30. Multiply out t...