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The first thing you need to do is collect all the 'like terms' on the same side of the equation. Start with the 'x' terms and remember to reverse the signs as you cross them over to the other side. 

1. Move everything to the same side: 2x^3-12X^2-10x=0 2.Take out a factor of 2x: 2x(x^2-6x-5)=0 3.Complete the square on the quadratic: 2x[(x-3)^2-14]=0

x ≤ -4.5

First lets times both sides by (6x -1) y(6x - 1) = 4(2 + x) now lets expand the brackets 6xy - y = 8 + 4x now lets move all the ones with x as a factor onto one side of the equation and the rest on the ot...

Solution: 

We can first write down the formula for the area of a circle which is pi*(radius)^2.

The radius of the circle is half the diameter, so radius= 1/2(8)=4cm.

Therefore the are...