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Solve the inequality 5x + 3 ≤ 3x − 6.

x ≤ -4.5

4298 Views

Make x the subject of the equation. y = 4( 2 + x )/ (6x -1)

First lets times both sides by (6x -1) y(6x - 1) = 4(2 + x) now lets expand the brackets 6xy - y = 8 + 4x now lets move all the ones with x as a factor onto one side of the equation and the rest on the ot...

Answered by Oliver O. • Maths tutor

5012 Views

Calculate the area of a circle of diameter 8cm

Solution:

We can first write down the formula for the area of a circle which is pi*(radius)^2.

The radius of the circle is half the diameter, so radius= 1/2(8)=4cm.

Therefore the are...

Answered by Headon H. • Maths tutor

16573 Views

Rearrange the following making a the subject: (a+2)/5 = 3a+b

(a+2)/5 = 3a+b ...first, we need to multiply both sides by 5

a + 2 = 5 (3a + b) ....to be able substract 3a from the right side we need to remove the bracket. We multiply the bracket by 5.

Answered by Katerina R. • Maths tutor

3114 Views

Expand the following: (4x+7)(7x-2)

Using the FOIL (Firsts, Outsides, Insides, Lasts) mnemonic, you can expand these two brackets. F: 4x x 7x = 28x^2 O: 4x x -2 = -8x I: 7 x 7x = 49x L: 7 x -2 = -14 Therefore the expansion as a whole is: 28...

Answered by Gem P. • Maths tutor

3792 Views