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Maths
GCSE

Solve this equation x^2 +4x - 5

Have you seen anything like this before? 

What do you understand by this equation? 

How do you expand brackets? Grid/smiles and eyebrows 

How confident are you with factors and times ...

ZM
Answered by Zeenat M. Maths tutor
3283 Views

Solve the simultaneous equations: 6a + b = 16 and 5a - 2b = 19

Rearrange the first equation to give b as the subject.

b = 16 - 6a

Then substitute that equation for b into the second equation.

5a - 2(16 - 6a) = 19

Simplify this equation (re...

FL
Answered by Francesca L. Maths tutor
3972 Views

Complete this substitution question: x^​3 - 25 = 103 - x^​3

Firstly, let's move the x^​3's onto the same side (and preferably keep them positive). Let's add x^​3 to both sides, which means the RHS will now read '2x^​3 - 25' and the LHS will read '103'. Next we wan...

AJ
Answered by Aoife J. Maths tutor
2897 Views

Solve the following simultaneous equation for x and y: 2x + 5y = 8, 4x + y = 7

Equation A: 2x + 5y = 8

Equation B: 4x + y = 7

2A: 4x + 10y = 16

2A - B: 9y = 9, Therefore y = 1

Sub y back into equation A to find x:  2x + 5 = 8,  2x ...

ND
Answered by Nicholas D. Maths tutor
5578 Views

solve (2x+3)/(x-4) - (2x-8)/(2x+1) = 1 leave answer in fraction form

times both sides by both denominators

= (2x+3)(2x+1) - (2x-8)(x-4) = (2x+1)(x-4)

times out brackets

= (4x2 + 8x +3) - (2x2 -16x +32) = 2x2 -7x -4

...
AH
Answered by Amber H. Maths tutor
3012 Views

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