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7x+3y-4 > 5y-19x

Adding 19x to both sides:

26x+3y-4 > 5y

Subtracting 3y from both sides:

26x-4 > 2y

Divide both sides by 2 to put the expression in its simplest...

Quadratic inequalities generally don't arrive in the standard quadratic form (Ax^2 + Bx +c) and so can be sometimes difficult to spot. However, if you see an X^2 - or brackets that expand to X^2 - on eith...

Factorise the quadratic into two brackets to make (x-3)(x-5)=0 Because the product of these brackets is zero then the value of one of the brackets must equal zero. In order for one of the brackets to have...