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Using the factorisation method.
the factorised solution will look like (x+a)(x+b) = 0
by multiplying these two brackets we get the equation:
x^2 + a.x+b.x + a....
WORKING OUT
3a3b+12a2b2+9a5b3
1) 3(a3b+4a2b2+3a5b3AWAnswered by Anna W. • Maths tutor4038 Views
To factorise 3a3b + 12a2b2 + 9a5b3, we need to deal with like elements together.Start with the integers. The highest common factor of 3, 12, and 9 is...
To do this, we first need to calculate the prime factorisations of 432 and 522, that is to say we need to break the numbers down into their prime factors.Let's start with 432. 432 = 2 x 216432 = 2 x ( 2 x...
We can use the formula method (for solving quadratic equations) to find 'roots' or values of x that satisfy or 'work out' for a given quadratic equation of an unknown variable (say x.) The formula is:x=-b...
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