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The answer is C) 10A Fuse.To calculate the current flowing to the kettle, you use the P=IV equation to work out that I=P/V. Putting P = 1200 and V = 230 into this equation gives I = 1200/230 = 5.217A. The...
Using Vp/Vs=Np/Ns, we can rearrange to get Ns= (VsNp)/VpSo, Ns = 8*50/4=100 turns.
Work done= F x d; where d= distance object has been moved through in same direction of force and F= resultant force. F=8 N.d=2 x 1000 m.WD = 2000 x 8 = 16000 J
The current is the number of electrons flowing through the wire per second. The voltage however, is the amount of energy each individual electron is carrying as it moves through the wire.
Energy used for one boil = (3.78 x 105 / 100) x 55Energy used for one boil = 2.079 x 105 J Energy lost per boil = 3.78 x 105 -2.079 x 105Energy lost per boil = ...
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