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Solve the following simulatenous equation to find the values of both x and y: 5x+2y=16 3x-y=14

x=4, y=-2

OG
Answered by Oliver G. Maths tutor
3296 Views

Solve the following ((3x + 1)/2x ) = 4

3x + 1 = 4(2x) 3x + 1 = 8x 1 = 5x x = 1/5

BL
Answered by Benjamin L. Maths tutor
4504 Views

'What's the difference between an aorist infinitive and a present one?'

Essentially the difference between the two is in what is known as the 'aspect' of the action they refer to, which can be either continuous or instantaneous. For example, whereas 'δει υμιν λεγειν' means 'y...

JB
1687 Views

How do you divide mixed fractions? e.g. (1(1/5)) / (3/4)

(1(1/5)) / (3/4)1(1/5) = 6/5therefore the question is(6/5) / (3/4)To divide a fraction, you simply swap the position of the numerator and denominator in the latter part of the example, and multiple the fr...

JM
Answered by Jack M. Maths tutor
3224 Views

Solve the simultaneous equations, x+y = 16, 5x -2y = 17

Multiply the first equation by 2 to obtain 2x+2y = 32,Then use the elimination technique and add the first equation into the second equation to get : 7x = 49 therefore divide by 7 to find x = 7 Sub this v...

MO
Answered by Matthew O. Maths tutor
3968 Views

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