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Using the substitution of u=6x+5 find the value of the area under the curve f(x)=(2x-3)(6x+%)^1/2 bounded between x=1 and x=1/2 to 4 decimal places.

dx=du/6 => (u-5)/6=x So the integral is now (2((u-5)/6)-3)(u^1/2) du/6 Which through simplifying becomes (1/36)(2u-28)(u^1/2)du = (1/36)(2u^3/2 -28u^1/2)du After integrating becomes (1/36)(4(u^5/2)/5 -...

JT
Answered by Joseph T. Maths tutor
3815 Views

Solve the equation to find the value of t. (5t+3)/4=1

Step 1: (5t+3)/4 = 1 Step 2: (5t+3)= 1 x 4 Step 3: 5t + 3 = 4 Step 4: 5t = 4 - 3 Step 5: 5t = 1 Answer: t = 1/5 

BM
Answered by Bhavya M. Maths tutor
5779 Views

How do I compare two texts of different genres in an essay?

Comparing texts of different genres can sometimes seem daunting, but is easier than you think. The most effective way to make the comparison is to think about the theme, or themes, that you are comparing ...

OC
Answered by Oliver C. English tutor
16415 Views

What is the best way to revise for a Maths A-level?

The best method to revise is through solving past questions and timed exam papers. As long as you have your notes and understand all the basic principles, then you just need to practice in order to avoid ...

AE
Answered by Ayah E. Maths tutor
8122 Views

Integration by parts: Integrate the expression x.ln(x) between 1 and 2.

Let $ denote the integral symbol, as I am limited here by my keyboard.

Recall the formula for integration by parts:

$ u.(dv/dx) dx = uv - $ u(dv/dx) dx

So to find $pi0...

RH
Answered by Rebecca H. Maths tutor
3095 Views

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