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First assess that the initial case of where n = 1 is true. In this case, 6+9=15=53, so we can see that the case is true.We can then assume that 6k+9 is a multiple of 5, so we can let 6...
32x(4x^2 + 3)^3
4sinx(cosx)^3 - 4cosx(sinx)^3
First we need to find the complementary function - the solutions of y'' -3y' + 2y = 0. By setting y=Ae^(kx) (A is a constant) we get :A(k^2 - 3k + 2)y = 0. This means k^2 - 3k + 2 = 0 =(k-1)(k-2). If 2 th...
Take 2 vectors on the plane, originating from the same point, that aren't parallel: P1-->P2 = P2-P1 = -4i+3j-kP1-->P3 = P3-P1 = 0i+0k-2kOne can then find the cross product of these two vectors to de...
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