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Solve the equation [(3x + 3)/2x] + 2x - 1 = -3

In this question we are trying to find all the possible solutions of the variable x that will satisfy the given equation. Firstly, we see there is a denominator on one of the terms so we multiply all the ...

CB
Answered by Chris B. Maths tutor
3189 Views

Solve x^2+6x+5=0 for x

x2+6x+5=(x+5)*(x+1)=0 therefore x+5=0 or x+1=0, hence x=-5 and x=-1

WR
Answered by William R. Maths tutor
3016 Views

Integrate y=x^2 between the limits x=3 and x=1

Integrate y=x^2 which is 1/3 x^3 Subsitute the limits, (1/3 (3)^3)-(1/3 (1)^3) 27/3 - 1/3 = 26/3

CW
Answered by Caleb W. Maths tutor
3579 Views

Given that y=((3x+1)^2)*cos(3x), find dy/dx.

As why is in the for y=uv where u and v are funtions of x, dy/dx=u'v+v'u (where ' implies the derivative) u=(3x+1)2, v=cos(3x) therefore using the chain rule u'=23(3x+1)=18x+6 and v'=-...

WR
Answered by William R. Maths tutor
3462 Views

x^2 - 10x + 33 ≡ (x - a)^2 + b. Work out the value of a and b.

x2 - 10x + 33 ≡ (x - a)2 + b Work out the value of a and b. Our aim here is to write the expression on the left in the same form as the one on the...

JC
Answered by Joshua C. Maths tutor
11266 Views

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