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Express 3(x^2) - 12x + 5 in the form a(x - b)^2 - c.

Starting with a(x - b)^2 - c, if we expand the bracket we get:

a(x^2 - 2xb + b^2) -c

Since we need to end up with the coefficient on x^2 being 3 and in the expression above x^2 is only multi...

LH
Answered by Lucy H. Maths tutor
9861 Views

Make x the subject of the equation. y = 4( 2 + x )/ (6x -1)

First lets times both sides by (6x -1) y(6x - 1) = 4(2 + x) now lets expand the brackets 6xy - y = 8 + 4x now lets move all the ones with x as a factor onto one side of the equation and the rest on the ot...

OO
Answered by Oliver O. Maths tutor
5162 Views

Calculate the area of a circle of diameter 8cm

Solution: 

We can first write down the formula for the area of a circle which is pi*(radius)^2.

The radius of the circle is half the diameter, so radius= 1/2(8)=4cm.

Therefore the are...

HH
Answered by Headon H. Maths tutor
17161 Views

Write the complex number Z=1/2+sqrt(3)/2j both as a function involving cos & sin, and as a function involving an exponential.

|Z| = sqrt(1/2^2 + (sqrt(3)/2)^2) = 1 arg(Z) = arctan((sqrt(3)/2)/(1/2)) = pi/3 Z = cos(pi/3) + jsin(pi/3) Z = e^j(pi/3) Apologies for the use of sqrt(), I have no way yet of using the symbol on my laptop...

SR
Answered by Sol R. Maths tutor
3781 Views

Let f(x) = 5x^4 + 6x^3 + 3, find dy/dx at x = 3

First we must differentiate the equation with respect to x. To differentiate you must multiply the coefficient (number in front) by the power of x, then subtract 1 from the power. So here we find dy/dx = ...

FK
Answered by Francesca K. Maths tutor
3280 Views

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