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We have our function of y = 1+2x-x² The gradient of a stationary (or turning) point is 0, in essence a peak or a trough. In order to determine the gradient, we need to differentiate our ...

FIrst of all we need to understand how cos 30° and tan 60° are found. Let's think of an equilateral triangle, all three angles of the triangle are equal and 60° and each side has length 2. Let's half the ...

= 2πr² + πd x height (= area of the 2 circle at either end + area of rectangular surface around the cylinder)

Let's first consider the differential of 2^x. We know that this becomes ln(2)*2^x. We can compare this to the integrand and see that this is very clos...

y = -16x² + 160x - 256 

x = 5

y = 144