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Make y the subject of the formula x=(2y-1)/(4-y)

1st step: we multiply the equation by (4-y) and we get: x(4-y)=(2y-1) 2nd step: we bring the equation to the form: 4x-xy=2y-1 3rd step: now we isolate all the y terms on the same side: 2y+xy=4x+1 4th step...

AB
Answered by Andrea B. Maths tutor
11342 Views

John ran a 450m race (2sf) in a time of 62 seconds (nearest second). Calculate the difference between his maximum and minimum average speed. (3sf)

S=D/T Max= 455(upper bound)/61.5(lower bound)= 910/123 m/s Min= 445(lower bound)/62.5 (upper bound) = 178/25 m/s Max - Min= 856/3075 m/s

CR
Answered by Christopher R. Maths tutor
4025 Views

There are 45 pupils in a class, 1/9 travel to school by train, 2/5 travel to school by car, 2/9 take the bus. Find how many students walk

First the number of children that travel by train can be found by dividing 45 by 9 to give 5. Since we know that double as many take the bus, as 2/9 is the double of 1/9,5x2=10 children take the bus. Then...

KS
Answered by Karina S. Maths tutor
13889 Views

x is inversely proportional to P. When P = 6, x =2. What does x = when P = 4?

We know x is inversely proportional to P, so immediately we know their relationship is of the form x = k/P , where k is a constant. We are also given some conditions we can use to solve for k: when x = 2,...

AS
Answered by Alec S. Maths tutor
3710 Views

Split the following expression into partial fractions of the form A/(x-3) + B/(4x+2) : (19x-15)/(4x+2)(x-3)

Set the expression equal to the form required in the solution. Multiply both sides by (4x-2)(x-3) to get rid of the denominator and acquire an expression of the form: 19x-15 = A(4x+2) + B(x-3). From here ...

AS
Answered by Alec S. Maths tutor
4604 Views

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