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Solve the simultaneous equations: y=x/2 + 2 and 2y+3x=12

Label the equations (1): y=x/2 + 2 and (2): 2y+3x=12. Firstly, multiply equation (1)by 2, this will give you (1a): 2y=x+4, then, substitute (1a) into (2). This gives you (x+4)+3x=12. Therefore, 4x+4=12. 4...

JB
Answered by Joseph B. • Maths tutor
6147 Views

Solve the equation x^2-9x+20=0

First, we need to factorise the equation on the left hand side, this can be done by finding two numbers that add together to make the 'b' coefficient (-9) and multiply to make the 'c' coefficient (20).

JB
Answered by Joseph B. • Maths tutor
29477 Views

If f'(x)=3x(x - 1), find f(x)

Due to notation difficulties, S = integral sign. This is a straightforward integration question, firstly we expand the brackets:

f'(x)=3x^2 - 3x f(x)=S(3x^2 - 3x)dx f(x)=3/3x^3 - 3/2x^2 + C f(x)=x^...

GR
Answered by Grace R. • Maths tutor
5061 Views

The point A lies on the curve y=5(x^2)+9x , The tangent to the curve at A is parralel to the line 2y-x=3. Find an equation to this tangent at A.

y-(any value of the function)=0.5(x-(any value in the domain))

e.g. Point with point A being (1,14) The answer would be y-14=0.5(x-1)

RA
Answered by Rehman A. • Maths tutor
3916 Views

Express cos(x) + (1/2)sin(x) in terms of a single resultant sinusoidal wave of the form Rsin(x+a)

cos(x) + (1/2)sin(x) :

Rsin(x + a) = R{sin(x)cos(a) + cos(x)sin(a)} = (1/2)sin(x) + (1)cos(x) (comparing coeffs.)

Therefore Rcos(a) = 1/2 and separately Rsin(a) = 1 So tan(a) = 2 and R^2 =...

HT
Answered by Hakkihan T. • Maths tutor
7619 Views

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