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Maths
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How do I find the equation of a tangent to a given point on a curve?

Let's take an example: Curve: y = x^2 Point: (2,4)

The equation of the tangent is going to be of the form y = mx + c (standard equation of a straight line), where m is the gradient of the line ...

TP
Answered by Theo P. Maths tutor
4276 Views

The line AB has equation 3x + 5y = 7, find; a) the gradient of AB b) the x-axis and y-axis intercepts c) sketch the graph

a) Rearrange equation into the form y = mx + c where m is the gradient and c is the y-axis intercept. Gradient AB = -3/5. b) The y-intercept is c which = 7/5. To find x-axis intercept we set y=0 and rearr...

WH
Answered by Will H. Maths tutor
5030 Views

Solve the following quadratic equation: x^2 + 3x + 2 = 0

Step 1: Find factors of the constant (The number with no x attached to it), In our case this is 2. The factors of 2 are: 1 & 2 and -1 & -2.

Step 2: The sum of the factors from step 1 must e...

JS
Answered by Jack S. Maths tutor
4420 Views

Solve for x: 2x^2 + 2x -24 = 0

  1. The general formula of a quadratic is ax^2 + bx + c -> this is a quadratic 2) Factorise using common factor (=2) -> 2(x^2 + x - 12) = 0 3) Factorise the quadratic to (x + m)(x + n): the two nu...
YZ
Answered by Yige Z. Maths tutor
10880 Views

Simplify: (3x+8)/5 > 2x + 1

  1. Multiply both sides by 5: 3x + 8 > 10 x + 5
  2. Move 3x to RHS by subtracting 3x from both sides: 8 > 7x + 5
  3. Move 5 to LHS by subtracting 5 from both sides: 3 > 7x
  4. Ma...
OD
Answered by Orlaith D. Maths tutor
4427 Views

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